Posted by Jay on Thursday, January 13, 2011 at 11:45pm.
I think the tutors like you to post each problem as a separate post.
O thanks for the tip. New here. Well and friend helped me figure out 1 and 2 since they were basically the same question. I found out that I had trouble actually doing the algebra once I had the equations. But I'm still a little confused on how to set up number 3.
3. 30-60-90 special triangle
draw this out to see that you need to find side a (shorter side) of triangle ABC
30-60-90 triangle have sides in the ratio of 1 : sqrt 3 : 2 (a : b : c)
Since side b = 10
cos 30 = b/c = 10/c
since ratio of b/c = sqrt 3/2
sqrt 3/2 = 10/c
c * sqrt 3 = 20
c = 20/sqrt 3 = 11.5470
Need to find side a
sin 30 = a/c = a/11.5470
since ratio of a/c = 1/2
1/2 = a/11.5470
a = 5.7735
from picture that you drew you will see
500 - side a = height of shorter blding
500 - 5.7735 = 494.2265'
The angle of elevation from a point on the ground to the top of a post is 15°. The point is 100 meters from the base of the post. To the nearest meter, how tall is the post?
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