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December 22, 2014

December 22, 2014

Posted by **Taylor** on Thursday, January 13, 2011 at 11:22pm.

a) Determine the distance from the archer to the target.

b) At what angle should the arrow be directed in to maximize its range?

- Physics -
**drwls**, Friday, January 14, 2011 at 12:39amThe direction (25 degrees north of east) is useless information. You can ignore it. If it is in the air 3.0 seconds,it takes 1.5 seconds to rise to maximum height. The vertical velocity component is g*1.5s = 14.7 m/s

To compute how far the arrow goes, you need to know the launch angle A from horizontal OR the horizontal velocity component. Neither has been provided.

b) 45 degrees. The range is

(V^2/g)*sin(2A) That is a maximum when A = 45 degrees.

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