Posted by Alex on Thursday, January 13, 2011 at 11:22pm.
If you want to use the e^kt function then you can find k the following way.
.5 = 1(e^2651k)
ln .5 = 2651k
k = ln.5/2651 = -.000261466
so we need:
10 = 100(e^ -.000261466t)
.1 = e^ -.000261466t
-.000261466t = ln .1
t = ln .1 / .000261466
t = 8806 years
or
Since you know you are dealing with half-life, we could use the equation
10 = 100 (.5)^(t/2651)
t/2651 = l .1 / ln .5
t = 8806
Related Questions
calculus - The rate at which an amount of a radioactive substance decays is ...
Pre Calculus - Exponential growth and decay find the half life of a radioactive ...
Chemistry - Which radioactive sample would contain the greatest remaining mass ...
Calc - A sample of a radioactive substance decayed to 93.5% of its original ...
Pre Calculus - Exponential Growth and Decay Find the half-life of a radioactive ...
math - 39mg radioactive with 1/2 life is decay total in 2.5 years. How many mg ...
Chemistry - Uranium-238 has half life of 4.51 * 10^9 years Uranium-234 has half ...
Calculus - The half life of a certain radioactive substance is 10 years. How ...
Math - D.E.Q. - The half-life of a radioactive isotope is the amount of time it ...
AP Calculus - An Initial amount of 100 grams of Thorium-234 decays according to ...
For Further Reading