Posted by Zukii on Thursday, January 13, 2011 at 11:13pm.
x^2 - x + 1 > 3
or
-x^2 + x - 1 > 3
case 1:
x^2 -x - 2 > 0
(x-2)(x+1) > 0
critical values are -1 and 2
(if we look at the parabola y = x^2 - x - 2, the x-intercepts are -1 and 2 and we want all values above the x-axis)
so x < -1 OR x > 2
case 2:
x^2 -x + 4 < 0
the corresponding equation x^2 - x + 4 = 0 has no real roots, so no value of x satisfies our inequation.
so x < -1 OR x > 2
Related Questions
algebra2 - solve the equation: First: x + 3y = 5 Second: 3x - y = 5 should i use...
Calculus - Work out the problem and explain your steps as you go please! 1. ...
Pre calculus - How do I solve this quadratic inequality? X2- 7x+10>0 the ...
math - I Wanted To Find The Square Root Of (1-2i) But I Didn't Know How To ...
Calculus (Urgent!!) - Hello everyone, I need help with the following problems. ...
Math - Solve the equation by first factoring the quadratic expression. 1. x2+4....
Math - Solve the equation by first factoring the quadratic expression. 1. x2+4....
Algebra II - 1.Solve: x(x2 + 16) = 0 2.Solve: 2x3 + 6x2 – x – 3 = 0 3...
calculus - solve the following equation Log1/3(x2+x)-log1/3(x2-x)=2 the 1/3 ...
algebra - Solve the asymptotes x x2 − 4 3x x2 âˆ&#...
For Further Reading
