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April 16, 2014

April 16, 2014

Posted by **siti** on Thursday, January 13, 2011 at 10:39pm.

acceleration of 2 m/s2 until it reaches a speed of 27 m/s. Afterwards it maintains this

speed. Also, when t = 0, car B located 2000 m down the road is traveling towards A at a

constant speed of 20 m/s. Determine the distance traveled by car A when they pass each

other.

- physics, dynamics -
**ayume90**, Saturday, January 15, 2011 at 3:03amfor car A

initial velocity u=0m/sec

acceleration=a=2m/s2

speed attained by A =27 m/sec

time taken by A to attain the speed =t

t=[v-u]/a=[27-0]/2=13.5m/sec2

distance traveled by car A in this time =s=ut+1/2at2

s= 0+0.5*2*13.5^2=182.25m

in this time distance traveled by B towards A=27*20/2=270m

so distance remaining between A and B after 27/2sec=2000-[182.25+270]=1547.75m

relative speed between A and B=27-[-20]=47m/sec

as they are moving in opposite direction.

now time taken by A to cross B =1547.75/47=33sec

in this time distance traveled by A=27*33=891m

hence the distances traveled by car A when they pass each

other=182.25+891=1073.25 m

- physics, dynamics -
**Anonymous**, Friday, August 24, 2012 at 3:02pmTwo cars are traveling along a straight road. Car a maintains a constant speed of 89 km/hr and car b maintains a constant speed of 119 km/hr. at t=0 car b is behind 38km from car a. How far will car a travel from t =0 before it is overtaken by car b. how long from t=0 will it take for this to happen

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