Need help problem solving--
A 500 space parking lot is packed with motorcycles and passenger cars, with only one vehicle in each space. How many motorcycles & cars r there if the total number of tires on the parked vehicles is 1650?
I think I have to do this in some kind of equation format, I am so confused.
175 motorcycles, 325 cars
motorcycles represented as x and cars, y
2x+4y=1650
2(500-y)+4y=1650
1000-2y+4y=1650
2y=650
y=325
2x+1300=1650
2x=350
x=175
Thanks so much Jasper:)
you posted this 2 times below
please check there for an answer before posting again
I answered this same question 2 times below where you asked the first time
To solve this problem, let's break it down step by step:
1. Let's assign variables to represent the number of motorcycles and cars in the parking lot. Let's say M represents the number of motorcycles and C represents the number of cars.
2. We know that there are 500 parking spaces in total, and each space can accommodate only one vehicle. Therefore, the total number of vehicles (motorcycles and cars) can be represented by the equation: M + C = 500.
3. Each motorcycle has 2 tires, and each car has 4 tires. The total number of tires on the parked vehicles can be represented by the equation: 2M + 4C = 1650.
4. Now we have a system of two equations with two variables:
Equations:
M + C = 500 (Equation 1)
2M + 4C = 1650 (Equation 2)
5. To solve this system of equations, you can either use substitution or elimination method. Let's use the elimination method here.
Multiply Equation 1 by 2 to make the coefficients of M equal in both equations:
2(M + C) = 2(500)
2M + 2C = 1000 (Equation 3)
Now subtract Equation 3 from Equation 2 to eliminate the M variable:
(2M + 4C) - (2M + 2C) = 1650 - 1000
2C = 650
Divide both sides of the equation by 2:
C = 325
6. Now substitute the value of C = 325 back into Equation 1 to find the value of M:
M + C = 500
M + 325 = 500
M = 500 - 325
M = 175
So, there are 175 motorcycles (M) and 325 cars (C) in the parking lot.