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March 31, 2015

March 31, 2015

Posted by **james** on Thursday, January 13, 2011 at 9:29pm.

- optimization -
**tchrwill**, Sunday, January 16, 2011 at 9:50amYou state that the altitude reached is defined by

y = ex - x^2/2e.

This compares to the normal expression for altitude of

h = Vo(t) - gt^2/2

where h = the maximum altitude, Vo = the initial velocity, t = the time and g = the acceleration due to gravity.

I therefore assume that your expression for the maximum altitude reached should read as

y = ex - gx^2/2

where e = the initial velocity, x = the time and g is as defined earlier.

Since you give no values for e, g or t, a specific quantitative answer is not possible.

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