Sunday
March 26, 2017

Post a New Question

Posted by on .

a 10 kg gun recoils with a speed of 0.1 meter per second as it fires a 0.001kg bullet. what is the speed of the bullet as it leaves the gun

  • Physics - ,

    Conservation of momentum:

    initial momentum=final momentum
    0=10kg*(-0.1m/s)+.001kg*deltaV
    solve for delta V

  • Physics - ,

    10.20

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question