Is this chemical equation correct and properly balanced, C3H4 + 5O2--> 3CO2 + 44H2O ?
To check if the chemical equation is correctly balanced, you need to make sure that the number of atoms of each element is the same on both sides of the equation. Let's break down each element in the equation:
C: There are 3 carbon (C) atoms on the left side and 3 carbon (C) atoms on the right side, so carbon is balanced.
H: There are 4 hydrogen (H) atoms on the left side and 88 hydrogen (H) atoms (44 H2O) on the right side. Since 4 is not equal to 88, hydrogen is not balanced.
O: There are 10 oxygen (O) atoms on the left side (5 O2 molecules) and 102 oxygen (O) atoms (3 CO2 + 51 H2O) on the right side. Since 10 is not equal to 102, oxygen is not balanced.
As we can see, the given chemical equation is not properly balanced. To balance it, you need to adjust the coefficients in front of the chemical formulas.
To balance the number of hydrogen atoms, you can place a coefficient of 22 in front of the water (H2O) on the right side, which will give you 44 hydrogen (H) atoms. The balanced equation becomes:
C3H4 + 5O2 → 3CO2 + 22H2O
Now, let's check the oxygen atoms again:
O: There are still 10 oxygen (O) atoms on the left side (5 O2 molecules), but on the right side, we have 6 oxygen (O) atoms from the carbon dioxide (3 CO2) and 44 oxygen (O) atoms from the water (22 H2O). This totals to 50 oxygen atoms.
To balance the oxygen atoms, we can multiply the oxygen (O2) on the left side by 25, giving us 25 O2, which will be equal to 50 oxygen (O) atoms on the right side. The balanced equation becomes:
C3H4 + 25O2 → 3CO2 + 22H2O
Now the equation is properly balanced, with the same number of atoms on both sides for carbon (C), hydrogen (H), and oxygen (O).
To determine whether the chemical equation is properly balanced, we need to count the number of atoms of each element on both sides of the equation.
On the reactant side (left side):
C: 3 atoms
H: 4 atoms
O: 10 atoms (5 from O2)
On the product side (right side):
C: 3 atoms
H: 88 atoms (44 from H2O)
O: 50 atoms (3 from CO2 and 44 from H2O)
As we can see, the number of H and O atoms is not balanced in the chemical equation. To balance the equation, we need to adjust the coefficients in front of the compounds.
The balanced equation is as follows:
C3H4 + 19O2 -> 3CO2 + 2H2O
Now, let's count the atoms again:
On the reactant side (left side):
C: 3 atoms
H: 4 atoms
O: 38 atoms (19 from O2)
On the product side (right side):
C: 3 atoms
H: 4 atoms
O: 38 atoms (3 from CO2 and 35 from H2O)
Now, the equation is correctly balanced with the same number of atoms on both sides.