What voltage is required to store 6.90 10-5 C of charge on the plates of a 7.00-µF capacitor?
Divide the desired charge by the value for the plates. Make sure you convert the micro F to 10^-6.
To determine the voltage required to store a certain amount of charge on a capacitor, you can use the formula:
V = Q / C
Where:
- V is the voltage across the capacitor
- Q is the charge on the capacitor
- C is the capacitance
In this case, the charge on the capacitor is given as 6.90 * 10^(-5) C, and the capacitance is given as 7.00 µF. However, it's important to note that the capacitance needs to be converted to farads (F) to use in the formula. One microfarad (µF) is equal to 10^(-6) farads, so:
C = 7.00 µF = 7.00 * 10^(-6) F
Now we can substitute the values into the formula to find the voltage:
V = (6.90 * 10^(-5) C) / (7.00 * 10^(-6) F)
To simplify this calculation, we can divide the numerator and denominator by 10^(-6) (since 10^(-6) / 10^(-6) = 1):
V = (6.90 * 10^(-5) C) / (7.00 * 1)
Now we can multiply 6.90 * 10^(-5) C by 10^6 / 7 to simplify the calculation further:
V = (6.90 * 10^(-5) C) * (10^6 / 7)
Using the appropriate exponent rule (a^b * a^c = a^(b+c)), we can combine the exponents:
V = 6.90 * (10^(-5) * 10^6 / 7) C
V = 6.90 * 10^(1) C / 7
To multiply a number by 10 raised to an exponent, we simply move the decimal point to the right by that number of places. In this case, as the exponent is positive 1, we move the decimal point one place to the right:
V = 0.690 C / 7
Finally, we can divide 0.690 C by 7:
V = 0.0986 C
Therefore, the voltage required to store 6.90 * 10^(-5) C of charge on the plates of a 7.00-µF capacitor is approximately 0.0986 V.