Posted by freddo on Thursday, January 13, 2011 at 3:07pm.
Hi,
Can someone check this for me please..
18 MB of data are to be transmitted over a a megabyte per second connection. How long should the complete transaction take, to the nearest 0.1s.
Size of file / data rate so,
18MB x 10^6 x 8 bits = 144,000,00
4 megabits per second = 4 x 10^6 = 4,000,000 bits per second
so the download time will be
144,000,000 / 4,000,000 = 36 seconds
my answer is 36 seconds is that right
next ,....
a 50 MB file compressed using a ratio of 10 what is the compressed file size
50MB / 10 = 5 MB
Is this correct ???
Thanks you

IT computer memory  PC, Thursday, January 13, 2011 at 4:30pm
You have to double check the question:
"18 MB of data are to be transmitted over a a megabyte per second connection"
Is it "a" megabyte connection" or is it "4 megabit connection"?

IT computer memory  freddo, Thursday, January 13, 2011 at 5:15pm
Hi
Sorry wasn't too clear
This should read 18MB of data are to be transmitted over a 4 megabits per second connection ... how long would it take to complete the transaction

IT computer memory  freddo, Thursday, January 13, 2011 at 5:15pm
to the nearest 0.1 s

IT computer memory  Ga, Tuesday, February 1, 2011 at 4:58pm
For the second part of your question...
Compressed file size = uncompressed / compression ratio
so
Compressed file size = 50MB / 10
Compressed file size = 5MB
I think

IT computer memory  Andy, Sunday, February 13, 2011 at 10:13am
No, incorrect.
Be carefull with this, your:
18MB x 10^6 x 8 bits = 144,000,00
Should in fact be:
18mb x 2^20 x 8 bits = 150,994,994
Your second part is correct, so its
4 megabits per second = 4 x 10^6 = 4,000,000
Answer:
150994994 / 4000000 = 37.75 seconds.
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