Posted by seth on Thursday, January 13, 2011 at 7:28am.
Yes, it is a buffer, at least in most cases. You might look at the mole NH3 and moles H2SO4. It may be that the H2SO4 has neutralized all of the NH3 present so you have an excess of H2SO4 (no NH3 present) along with the ammonium sulfate salt and that would not be a buffer.
2NH3 + H2SO4 ==> (NH4)2SO4
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