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Posted by CJ on Thursday, January 13, 2011 at 1:23am.

If sinθ=1/5 and θis in Quadrant I, find the exact value of 2θ.

Use the double angle formula: sin(2θ)=2sin(θ)cos(θ) given sin(θ)=1/5 cos(θ)=sqrt(1-(1/5)²))=sqrt(24)/5

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