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March 24, 2017

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Complete the table below:
For each of the following sets pick the compound with the highest conductivity in a 1 M aqueous solution.
(Enter the number at the top of the column containing the correct answer.)
1 2 3 Answers
a HCl HC2H3O2 H2PO4–
b KNO3 Ca(NO3)2 HNO3
c CH3OH NaOH HOC6H5
d Li2CO3 Na2CO3 K2CO3
e NaCl MgCl2 AlCl3

  • Conductivity - ,

    Look for the compound which in a dilute solution has the most ions. for instance, in b

    KNO3 is completed ionized,2 ions per molecule
    Ca(NO3)2, three ions, but one of them carries two charges, so in fact one moleucle can break up to carry 5 net charges.
    HNO3, 100 precent dissoacated, but two ions per molecule.
    Answer: circle calcium nitrate.

  • Conductivity - ,

    I still don't understand. Can someone help, and elaborate more?

  • Conductivity - ,

    for B Ca(NO3)2 is NOT the right answer. i got it wrong.

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    lol UCI students

  • Conductivity - ,

    Yes, UCI students. We haven't learned this in lecture.

  • Conductivity - ,

    I know that HCl is one of the correct choices

  • Conductivity - ,

    hey UCI!

    a. HCl
    b. HNO3
    c. NaOh
    d. K2CO3, also in the lab we did. it all depends on the cation (k, li, and na) which one has the highest mass
    e. AlCl3 (that was in the lab we did.)

  • Conductivity - ,

    you are my hero.

  • Conductivity - ,

    its wrong...^^^^^^^ is wrong!! :(

  • Conductivity - ,

    never mind!!!! its right lol! dude u guys.. my chem teacher didn't go over this neither did the TA.....

  • Conductivity - ,

    You are seriously my hero.

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    you are amazing!

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    UCI FTW. Haha webworks has NOTHING to do with lecture. They don't correspond, it suuuucckkks.

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    omgggg yay..i thought i was never going to figure this out....i freaking HATE webworks

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    Do we really need to know all of this for the lecture AND lab??

    Are these going to be on the test?

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    chem lab uci 2012! suffering with this a year later =/

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    YEA UCI chem lab where 2units > 4 units

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    Thanks man.

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    Thank gosh... herooooo.... I have no clue with these webwork question

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