y=2over3=1

dont know how 2 solve it 2 get the y-intercept
dont know how 2 graph it
please help and explain it

please

To solve the equation and find the y-intercept, we need to properly understand what the equation means.

The equation you provided is a bit unclear. It seems like you have written "y = 2/3 = 1," which doesn't make sense. However, I will assume that you intended to write something else.

If you have an equation in the form y = mx + b, where m is the slope and b is the y-intercept, then you can find the y-intercept by looking at the equation.

In this case, there seems to be some confusion in the equation you provided. Let's assume the equation is y = 2x/3 + 1, which is a linear equation in slope-intercept form (y = mx + b).

To find the y-intercept, we can set x = 0 and solve for y. So, when x = 0, we have:

y = (2*0)/3 + 1
y = 0/3 + 1
y = 0 + 1
y = 1

Therefore, the y-intercept is (0, 1). This means that the graph of the equation intersects the y-axis at the point (0, 1).

To graph the equation, you can start by plotting the y-intercept point, (0, 1), on the coordinate plane. Then, based on the slope, which is 2/3 in this case, you can find additional points by moving up 2 units and right 3 units. Connect these points, and you will have a straight line that represents the graph of the equation.

I hope this explanation helps you understand how to solve the equation and graph it. If you have any further questions, feel free to ask!