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January 25, 2015

January 25, 2015

Posted by **Tabby** on Wednesday, January 12, 2011 at 6:38pm.

2. Solve: 2 sin x - 1 = 0 for 0° ≤ x < 360°

3. Solve: sinē x = cosē x for 0° ≤ x < 360°

4. Solve: sin x - 2sin x cos x = 0 for 0 ≤ x < 2pi.

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