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A certain spring stretches 5.3 cm when it
supports a mass of 0.65 kg .
If the elastic limit is not reached, how far
will it stretch when it supports a mass of
10 kg ? Answer in cm

  • physics -

    Deflection will be proportional to the weight applies (Hooke's Law).

    X = Deflection = k * mass

    X2/X1 = M2/M1

    X2 = (M2/M1)*X1

    Multiply 5.3 cm by 10/0.65 for the answer.

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