Monday
March 27, 2017

Post a New Question

Posted by on .

sinA= 3/5 and C=17
Finding a and b

  • trigonometry - ,

    sin A = 3/5 = a/c

    if side a = 3 and side c = 5
    you should recognize this as a
    special rt triangle of 3-4-5
    so b = 4

    If not
    a^2 + b^2 = c^2
    3^2 + b^2 = 5^2
    b^2 = 16
    b = 4

    so, a = 3, b = 4

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question