Posted by **julie** on Wednesday, January 12, 2011 at 3:21pm.

A 215 g mass is attached to a spring and executes simple harmonic motion with a period of 0.250 s. If the total energy of the system is 2.30 J.

(a) Find the force constant of the spring.

135.81 N/m

(b) Find the amplitude of the motion.

i just need help with what equation i should use. im stumped on this question.

- physics -
**drwls**, Wednesday, January 12, 2011 at 4:28pm
The period is

P = 2 pi sqrt(k/m)

Use that and the mass to get the spring constant, k.

The total energy of the system is

(1/2) k X^2 = 2.30 J,

where X is the amplitude. .

Knowing that and k, solve for X.

## Answer This Question

## Related Questions

- Physics - A 200-g block is attached to a horizontal spring and executes simple ...
- physics - A .255 kg mass is attached to a spring and executes simple harmonic ...
- physics - A .436 kg mass is attached to a spring and executes simple harmonic ...
- ap physics - A 0.461 kg mass is attached to a spring and executes simple ...
- PHYSICS - A 0.181 kg mass is attached to a spring and executes simple harmonic ...
- physics - a mass of 0.2kg is attached to a spring of negligible mass. if the ...
- physics - A 0.125 kg mass is attached to a spring and undergoes simple harmonic ...
- physiscs - mass of 0.2 kg is attached to a spring of negligible mass. I the mass...
- Chemistry - A mass of 0.2 kg is attached to a spring of negligible mass. I the ...
- Physics - The period of motion of an object-spring system is T = 0.474 s when an...

More Related Questions