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Probability Please help!?!?

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A lottery is set up in which players pick six numbers from the set 1, 2, 3, ... , 39, 40. How many different ways are there to play this lottery? (In this game the order in which the numbers are picked does NOT matter.)

  • Probability Please help!?!? - ,

    The number of different combinations is
    C(40,6) or 40!/(6!34!) = 3 838 380

  • Probability Please help!?!? - ,

    Combination of 40 taken 6 at a time
    nCr = nPr/r!
    nPr = n!/(n - r)!
    nCr = (n!/(n - r)!) /r!
    n = 40, r = 6
    40C6 = 40P6/6! = 40!/34! / 6!
    = 40!/(6!*34!)
    = 40*39*38*37*36*35/(6*5*4*3*2*1)
    = 2,763,633,600/720
    = 3,838,380

    I am not a tutor but this is right IF this is a combination of 40 taken 6 at a time (I checked my math in an online calculator)

  • Probability Please help!?!? - ,

    if,89,88,45,9,33, were selected from 1-90, what are the next five numbers to be selected.

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