Posted by Billy on Wednesday, January 12, 2011 at 2:16pm.
A lottery is set up in which players pick six numbers from the set 1, 2, 3, ... , 39, 40. How many different ways are there to play this lottery? (In this game the order in which the numbers are picked does NOT matter.)

Probability Please help!?!?  Reiny, Wednesday, January 12, 2011 at 3:52pm
The number of different combinations is
C(40,6) or 40!/(6!34!) = 3 838 380

Probability Please help!?!?  helper, Wednesday, January 12, 2011 at 4:11pm
Combination of 40 taken 6 at a time
nCr = nPr/r!
nPr = n!/(n  r)!
nCr = (n!/(n  r)!) /r!
n = 40, r = 6
40C6 = 40P6/6! = 40!/34! / 6!
= 40!/(6!*34!)
= 40*39*38*37*36*35/(6*5*4*3*2*1)
= 2,763,633,600/720
= 3,838,380
I am not a tutor but this is right IF this is a combination of 40 taken 6 at a time (I checked my math in an online calculator)

Probability Please help!?!?  Hafiz Baba, Wednesday, July 8, 2015 at 1:18am
if,89,88,45,9,33, were selected from 190, what are the next five numbers to be selected.
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