Posted by **m** on Wednesday, January 12, 2011 at 11:29am.

Using the formula v=20(1.222)^t and v is the value and t=0 which is the year 1971. What year will the set be worth 1500?

I input this into the formula to get

1500=20(1.222)

The 20(1.222) is 24.44 not sure how to figure out the year. I believe I just add the 24 years to 1971 to get 1995 but not sure about that.

- math -
**Henry**, Thursday, January 13, 2011 at 7:16pm
V = 20(1.222)t = 1500,

20(1.222)t = 1500,

(1.222)^t = 1500 / 20 = 75,

Take the log of both sides:

t*log(1.222) = log75,

divide both sides by log(1.222):

t=log75/log(1.222)=1.8751 / 0.087071 =

21.53.

yr. = 1971 + 21 = 1992.

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