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July 2, 2015

Homework Help: Physics

Posted by ali on Wednesday, January 12, 2011 at 12:30am.

A particle has a charge of +1.5 C and moves from point A to point B, a distance of 0.18 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA − EPEB = +9.50 10-4 J.
(a) Find the magnitude and direction of the electric force that acts on the particle.
magnitude________ N
direction _________ (amongst, against, perpendicular to?)

(b) Find the magnitude and direction of the electric field that the particle experiences.
magnitude________N/C
direction __________ (amongst, against, perpendicular to?)

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