Posted by **Tara** on Tuesday, January 11, 2011 at 7:50pm.

Original Question:

A block hangs in equilibrium from a vertical spring. When a second identical block is added, the original block sags by 5.00 cm. What is the oscillation frequency of the two block system?

bobpursley s'ltn:

F=kx = mg

x=mg/k

but for the second block we have

x+.05=2mg/k

setting the x equal..

mg/k-2mg/k=-.05

-mg/k=-.05

k= mg/.05

now frequency:

f= 1/2pi sqrt (k/m)

put that k int the expression, and you have the answer

Okay bob, I did that and got 0.112 when my calculator was in degrees, but I know it needs to be in radians. So I got 21.99 when my calculator was in radians. I think I may just be entering it into my calculator incorrectly.

## Answer This Question

## Related Questions

- Physics - A block hangs in equilibrium from a vertical spring. When a second ...
- Physics - A block has mass 800 g, whose is fasten to a spring with spring ...
- Spring Physics - A block of mass 3 kg is hung from a spring, causing it to ...
- physics - A block with mass m =7.3 kg is hung from a vertical spring. When the ...
- physics - A horizontal spring with a spring constant of 22 N/m has a 600 gram ...
- physics - A horizontal spring with a spring constant of 22 N/m has a 600 gram ...
- physics - A simple harmonic oscillator consists of a 1.1 kg block attached to a ...
- physics - An oscillator consists of a block attached to a spring (k = 299 N/m). ...
- physics - An oscillator consists of a block attached to a spring (k = 299 N/m). ...
- physics - An oscillator consists of a block attached to a spring (k = 299 N/m). ...

More Related Questions