Posted by **Tara** on Tuesday, January 11, 2011 at 7:50pm.

Original Question:

A block hangs in equilibrium from a vertical spring. When a second identical block is added, the original block sags by 5.00 cm. What is the oscillation frequency of the two block system?

bobpursley s'ltn:

F=kx = mg

x=mg/k

but for the second block we have

x+.05=2mg/k

setting the x equal..

mg/k-2mg/k=-.05

-mg/k=-.05

k= mg/.05

now frequency:

f= 1/2pi sqrt (k/m)

put that k int the expression, and you have the answer

Okay bob, I did that and got 0.112 when my calculator was in degrees, but I know it needs to be in radians. So I got 21.99 when my calculator was in radians. I think I may just be entering it into my calculator incorrectly.

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