Physics
posted by Tara on .
A block hangs in equilibrium from a vertical spring. When a second identical block is added, the original block sags by 5.00 cm. What is the oscillation frequency of the two block system?

F=kx = mg
x=mg/k
but for the second block we have
x+.05=2mg/k
setting the x equal..
mg/k2mg/k=.05
mg/k=.05
k= mg/.05
now frequency:
f= 1/2pi sqrt (k/m)
put that k int the expression, and you have the answer.