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April 20, 2014

April 20, 2014

Posted by **Drake** on Tuesday, January 11, 2011 at 5:55pm.

(at zero initial speed) from the top of a(n)

146 m high hill.

The acceleration of gravity is 9.8 m/s2 .

Neglect friction and air resistance and de-

termine the bobsled’s speed at the bottom of

the hill.

Answer in units of m/s.

- physic -
**bobpursley**, Tuesday, January 11, 2011 at 5:59pmThe change in Kinetic Energy has to be equal to the change in Potentialenergy.

1/2 mv^2=mg*146

v^2=2g(146)

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