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March 30, 2017

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/6x^2=2-x

/=radical sign

  • algebra - ,

    So I read that as

    √(6x^2) = 2-x

    square both sides
    6x^2 = 4 - 4x + x^2
    5x^2 + 4x - 4 = 0

    using the formula
    x = (-4 ± √96)/10
    = (-2 ±2√6)/5

    I tested both answers in the original equation.
    They both work

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