algebra
posted by math on .
/6x^2=2x
/=radical sign

So I read that as
√(6x^2) = 2x
square both sides
6x^2 = 4  4x + x^2
5x^2 + 4x  4 = 0
using the formula
x = (4 ± √96)/10
= (2 ±2√6)/5
I tested both answers in the original equation.
They both work