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November 27, 2014

November 27, 2014

Posted by **math** on Tuesday, January 11, 2011 at 9:16am.

/=radical sign

- algebra -
**Reiny**, Tuesday, January 11, 2011 at 11:33amSo I read that as

√(6x^2) = 2-x

square both sides

6x^2 = 4 - 4x + x^2

5x^2 + 4x - 4 = 0

using the formula

x = (-4 ± √96)/10

= (-2 ±2√6)/5

I tested both answers in the original equation.

They both work

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