Wednesday

July 30, 2014

July 30, 2014

Posted by **anon** on Monday, January 10, 2011 at 10:09pm.

Be sure to draw a right triangle and letter it properly.

how can i solve the math in this problem. i know i would have to use the Pythagoream Theorem but i dont know how to set the problem up first.

- trigonometry. -
**bobpursley**, Monday, January 10, 2011 at 10:19pmSinA= b/C=3/4

you are given C, so b= 3/4 * 17

then a can be found from a^2+b^2=C^2

- trigonometry. -
**Reiny**, Monday, January 10, 2011 at 10:22pmyour question makes no sense

If you have a right-angled triangle where

sinA = 3/5, then the opposite side to vertex A is 3 and the hypotenuse is 5,

by Pythagoras it is easy to show that the third side is 4

(you should have recognized the 3-4-5 right-angled triangle)

if sinA = 3/5, then angle A is appro 37.9°

what does C=17 mean?

- trigonometry. -
**anon**, Monday, January 10, 2011 at 11:52pmsinA= 3/5 and C=17

Finding a and b

would this work as an answer ..?

sinA = opp/hyp = a/c = 3/5 = 3*3.4/5*3.4 = 10.2/17

a = 10.2

Applying Pythagoream Theorem a^2 + b^2 = c^2

- trigonometry. -
**anon**, Monday, January 10, 2011 at 11:55pmb= sqrt 17^2 - 10.2^2 = 13.6

??

**Related Questions**

Math(Geometry) - In the diagram below(no diagram but details will be provided), ...

math right triangle - the hypotenuse of a right triangle is 1 inch longer than ...

math - Suppose we draw semicircles on the sides of a triangle and compute their ...

math - The legs of a right triangle are 3 and 4 units long. Find the lengths, to...

Trigonometry - Triangle ABC is a right triangle with right angle at C. CD is ...

math - The vertices of a triangle are listed below. H(-2,4), I(22,4), J(10,-1) ...

trig help - I need help finding sinA if cosA=(-3/5) and A is greater than 90 ...

Precalc/Triangles - Draw and solve any triangles satisfying alpha = 29 degrees a...

Pre-Calc - Consider a non-right triangle. a=39 b=25 c = 24.(a,b,c are the sides...

college geometry - Given: right triangle ABC with right angle at C, AC=22 and BC...