A constant net force of 390 N is applied upward to a stone that weighs 31 N. The upward force is applied through a distance of 2.0 m, and the stone is then released. To what height, from the point of release, will the stone rise? Assume that air resistance is negligible.

well, the energy given to the stone in kinetic motion is net force*distance or

KE=(390-31)*2 and that is equal to the change in PE that will happen, mgh

mgh=(359*2 solve for h.

To find the height to which the stone will rise, we need to use the concept of work and energy.

First, let's calculate the work done on the stone when the net force is applied upward through a distance of 2.0 m:
Work = Force * Distance

Here, the net force is 390 N and the distance is 2.0 m:
Work = 390 N * 2.0 m
= 780 J

The work done on the stone is equal to the change in its potential energy. As the stone rises to a certain height, its potential energy increases.

The potential energy (PE) of an object can be calculated using the formula:
PE = m * g * h

Where:
m is the mass of the object (in kg)
g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth)
h is the height (in meters)

Now, let's rearrange the formula to solve for the height (h):
h = PE / (m * g)

The mass of the stone is given as weighing 31 N. To convert this to mass, we divide by the acceleration due to gravity (g):
m = Weight / g
= 31 N / 9.8 m/s^2
= 3.163 kg (approximately)

Substituting the values into the formula, we can calculate the height:
h = 780 J / (3.163 kg * 9.8 m/s^2)
= 24.61 m (approximately)

Therefore, the stone will rise to a height of approximately 24.61 meters from the point of release.