Write the following expression as one logarithm: 2logx-log4-log3+logx.

Simplify your answer.

see

http://www.jiskha.com/display.cgi?id=1294704010

That does not seem right to me because when i graph it, they turn out different.

I am using the 3 major laws of logs

logA + logB = log(AB)
logA - logB = log(A/B)
nlogA = log (A^n)

so again...

2logx-log4-log3+logx
= log(x^2) -log4-log3 + logx
= log((x^2)(x)/((3)(4))
= log (x^3/12)

You must be graphing it incorrrectly.

To simplify the expression and write it as a single logarithm, we can use the properties of logarithms.

The first property states that the sum of logarithms is the same as the logarithm of the product of the corresponding values:
log(a) + log(b) = log(a * b)

Using this property, let's simplify the expression step by step:

2log(x) - log(4) - log(3) + log(x)

Next, we can use the property of logarithms that states the difference of logarithms is equivalent to the logarithm of the division of the corresponding values:
log(a) - log(b) = log(a / b)

The expression becomes:

log(x^2) - log(4) - log(3) + log(x)

Now, we can use the property that states the logarithm of a power can be rewritten as the power multiplied by the logarithm of the base:
log(a^b) = b * log(a)

We can apply this property to simplify the expression further:

log(x^2) - log(4) - log(3) + log(x)

= 2log(x) - log(4) - log(3) + log(x)

= 2log(x) + log(x) - log(4) - log(3)

= log(x^2) + log(x) - log(4) - log(3)

Finally, we can combine the terms using the first logarithmic property mentioned above:

= log(x^2 * x / (4 * 3))

= log(x^3 / (4 * 3))

So, the expression 2log(x) - log(4) - log(3) + log(x) can be simplified to log(x^3 / (4 * 3)).