Posted by **matt** on Monday, January 10, 2011 at 7:19pm.

Write the following expression as one logarithm: 2logx-log4-log3+logx.

Simplify your answer.

- PreCalc -
**Reiny**, Monday, January 10, 2011 at 7:22pm
see

http://www.jiskha.com/display.cgi?id=1294704010

- PreCalc -
**matt**, Monday, January 10, 2011 at 7:25pm
That does not seem right to me because when i graph it, they turn out different.

- PreCalc -
**Reiny**, Monday, January 10, 2011 at 10:07pm
I am using the 3 major laws of logs

logA + logB = log(AB)

logA - logB = log(A/B)

nlogA = log (A^n)

so again...

2logx-log4-log3+logx

= log(x^2) -log4-log3 + logx

= log((x^2)(x)/((3)(4))

= log (x^3/12)

You must be graphing it incorrrectly.

## Answer this Question

## Related Questions

- Math - Make into one log function: 2logx-log4-log3+logx
- Math - Make into one log function: 2logx-log4-log3+logx
- math - Make into one log function: 2logx-log4-log3+logx
- Pre-Calc - Make into one log function: 2logx-log4-log3+logx
- Algebra 2 - Simplify: 1. 2log10^5+log10^4 2. 2log3^6-log3^4 3. log4^40-log4^5 4...
- math - express the following as a single logarithm log2+log3+log4
- algebra - I am supposed to write each logarithmic expression as a single ...
- Math - Express the following as a logarithm and simplify. 1. log(3x^2 + 11x - 20...
- Math - Express the following as a logarithm and simplify. 1. log(3x^2 + 11x - 20...
- math - I tried everthing but,I couldnt solve it. Please help me.the answer at ...

More Related Questions