Posted by **matt** on Monday, January 10, 2011 at 7:19pm.

Write the following expression as one logarithm: 2logx-log4-log3+logx.

Simplify your answer.

- PreCalc -
**Reiny**, Monday, January 10, 2011 at 7:22pm
see

http://www.jiskha.com/display.cgi?id=1294704010

- PreCalc -
**matt**, Monday, January 10, 2011 at 7:25pm
That does not seem right to me because when i graph it, they turn out different.

- PreCalc -
**Reiny**, Monday, January 10, 2011 at 10:07pm
I am using the 3 major laws of logs

logA + logB = log(AB)

logA - logB = log(A/B)

nlogA = log (A^n)

so again...

2logx-log4-log3+logx

= log(x^2) -log4-log3 + logx

= log((x^2)(x)/((3)(4))

= log (x^3/12)

You must be graphing it incorrrectly.

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