This question HATES ME!
Which value would best describes the data? 8, 9, 10, 12, 14, 15, 18, 18, 63.
A-mean
B-mode
C-median
D-
Since 63 is an outlier and doesn't fit with the other data, I'd choose the median as the best descriptor.
Jan. 27 2011
What if D-Outlier then would the answer be the same
**Please explain how u would get the answer??
yes how do you get the answer
To determine which value best describes the data, you need to understand the concepts of mean, mode, median, and range. Here's a brief explanation of each:
1. Mean: The mean, also known as the average, is calculated by adding up all the values in the data set and dividing the sum by the total number of values. It gives you an idea of the "central" value of the data.
2. Mode: The mode is the value that appears most frequently in the data set. It represents the most common value.
3. Median: The median is the middle value when the data is arranged in numerical order. If there is an even number of values, the median is the average of the two middle values. It provides an indication of the "middle" value in the data set.
4. Range: The range is the difference between the highest and lowest values in the data set. It gives you an idea of the spread or variability of the data.
Now let's apply these concepts to the given data set: 8, 9, 10, 12, 14, 15, 18, 18, 63.
To find the mean, add up all the values and divide by the total number of values:
(8 + 9 + 10 + 12 + 14 + 15 + 18 + 18 + 63) / 9 = 16.11 (rounded to 2 decimal places)
To find the mode, identify the value(s) that appear most frequently in the set. In this case, there is no value that repeats, so there is no mode.
To find the median, arrange the values in numerical order:
8, 9, 10, 12, 14, 15, 18, 18, 63
The median is the middle value, which is 14 in this case.
To find the range, subtract the smallest value from the largest value:
63 - 8 = 55
So, the possible options are:
A) Mean = 16.11
B) Mode = No mode
C) Median = 14
D) Range = 55
Based on the calculations, the best description for the given data set would be C) Median = 14, as it represents the middle value in the set.