Posted by **Jands** on Monday, January 10, 2011 at 4:39pm.

Find the intercept, relative extrema, point of inflection, and asymptotes of the function(if they exist)of:

y = (x^2 + 1)/(x^2 - 9)

- Calculus -
**drwls**, Monday, January 10, 2011 at 5:22pm
The intercept is the y value when x = 0. That's pretty easy.

The relative extrema occur where dy/dx = 0

The inflection point is where d^2y/dx^2 = 0

The asymptotes are where the denominator of y(x) is zero: x = 3 and -3.

Now you have some differentiating to do.

- Calculus -
**karen **, Saturday, October 27, 2012 at 1:49am
y=0^2+1/0^2+9 y = 1/9 y intecept

## Answer this Question

## Related Questions

- Calculus - Find the intercept, relative extrema, point of inflection, and ...
- Calculus - Find the intercept, relative extrema, point of inflection, and ...
- Calculus - Find the intercept, relative extrema, point of inflection, and ...
- APCalculus - For the function y=4-2x^2+1/6x^4 find the following: Domain x and y...
- calculus - Find all relative extrema and points of inflection of the function: f...
- APCalculus - For the function y=2sin(x)-cos^2(x) on [0, 2pi] find the following...
- calculus - Find any relative extrema and any points of inflection if they exist ...
- Relative Extrema: AP Calculus - Consider the function f(x)= (3/4)x^4-x^3-3x^2+6x...
- Calculus - Find all extrema, inflection points, and asymptotes where applicable ...
- calculus - find the relative extrema and points of inflection, if possible, of y...

More Related Questions