so i know that when you have an isosceles triangle has 2 equal sides, and the 2 angles created by those sides are also equal . if a question gives me the angle at the top ( which is 40 degrees ), how do i find the 2 equal angles at the bottom ?

Since the 3 angles of a triangle = 180

180 - 40 = 140
140/2 = 70
70 + 70 + 40 = 180

All of the angles in a triangle total 180, so 180-40=140, 140/2=70

To find the two equal angles at the bottom of an isosceles triangle when you are given the angle at the top, you can use the fact that the sum of the angles in a triangle is always 180 degrees.

In an isosceles triangle, the two equal angles at the bottom are congruent. Let's call each of those angles "x."

Since we know that the sum of the angles in a triangle is 180 degrees, we can set up an equation:

40 degrees (angle at the top) + x degrees + x degrees = 180 degrees

Simplifying the equation, we have:

40 degrees + 2x degrees = 180 degrees

Now, subtract 40 degrees from both sides:

2x degrees = 180 degrees - 40 degrees
2x degrees = 140 degrees

Finally, divide both sides by 2:

x degrees = 140 degrees / 2
x degrees = 70 degrees

So each of the two equal angles at the bottom of the isosceles triangle measures 70 degrees.