Give 5 possible dimensions for the following rectangle with the perimeter given. Perimeter= 12x+20
the sum of length plus width has to be 6x + 10
so make up any 5 different pairs whose sum is 6x+10
e.g.
length = 4x+8
width = 2x + 2
just make up 4 more like that.
Boo boo doo doo ha ha
To find 5 possible dimensions for a rectangle with the given perimeter, we can start by setting up an equation using the formula for the perimeter of a rectangle:
Perimeter = 2 * (Length + Width)
Given: Perimeter = 12x + 20
Setting up our equation:
12x + 20 = 2 * (Length + Width)
We can simplify this equation by dividing both sides by 2:
6x + 10 = Length + Width
Now, we need to find 5 possible dimensions that satisfy this equation. Let's assume the length and width can be positive integers.
Possible Dimension 1:
Length = 6x + 9, Width = 1
Substituting these values into our equation:
6x + 10 = (6x + 9) + 1
This equation is true, so Length = 6x + 9 and Width = 1 is a possible dimension.
Possible Dimension 2:
Length = 5x + 8, Width = 2
Substituting these values into our equation:
6x + 10 = (5x + 8) + 2
This equation is true, so Length = 5x + 8 and Width = 2 is a possible dimension.
Possible Dimension 3:
Length = 4x + 7, Width = 3
Substituting these values into our equation:
6x + 10 = (4x + 7) + 3
This equation is true, so Length = 4x + 7 and Width = 3 is a possible dimension.
Possible Dimension 4:
Length = 3x + 6, Width = 4
Substituting these values into our equation:
6x + 10 = (3x + 6) + 4
This equation is true, so Length = 3x + 6 and Width = 4 is a possible dimension.
Possible Dimension 5:
Length = 2x + 5, Width = 5
Substituting these values into our equation:
6x + 10 = (2x + 5) + 5
This equation is true, so Length = 2x + 5 and Width = 5 is a possible dimension.
Therefore, 5 possible dimensions for the rectangle with the given perimeter are:
1) Length = 6x + 9, Width = 1
2) Length = 5x + 8, Width = 2
3) Length = 4x + 7, Width = 3
4) Length = 3x + 6, Width = 4
5) Length = 2x + 5, Width = 5