A ball initially at rest rolls down a hill with an acceleration of 2.7 m/s2.
If it accelerates for 8.1 s, how far will it move?
Answer in units of m.
d=0.5at^2 = 0.5 * 2.7 * (8.1)^2=88.6m.
To find the distance the ball will move, we can use the formula:
distance = (1/2) * acceleration * time^2
Given that the acceleration is 2.7 m/s^2 and the time is 8.1 s, we can substitute these values into the formula:
distance = (1/2) * 2.7 * (8.1)^2
First, we need to square the time: 8.1^2 = 65.61
Now, let's calculate the multiplication inside the parentheses: (1/2) * 2.7 * 65.61 = 88.7685
Rounding this value to the nearest meter, the distance the ball will move is approximately 89 m.