Posted by Emily on Monday, January 10, 2011 at 12:57pm.
So you want the t value which produces the max and min of the function, that is,
h '(t) = 0
5cos30(t-5) (30) = 0
cos 30(t-5) = 0
we know cos π/2 = 0 and cos 3π/2 = 0
30(t-5) = π/2 or 30(t-5) = 3π/2
t = 5.052 or t = 5.157
You did not define t, so you will have to make sense out of the value of t above.
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