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January 31, 2015

January 31, 2015

Posted by **Emily** on Monday, January 10, 2011 at 12:57pm.

- Math -
**Reiny**, Monday, January 10, 2011 at 3:00pmSo you want the t value which produces the max and min of the function, that is,

h '(t) = 0

5cos30(t-5) (30) = 0

cos 30(t-5) = 0

we know cos π/2 = 0 and cos 3π/2 = 0

30(t-5) = π/2 or 30(t-5) = 3π/2

t = 5.052 or t = 5.157

You did not define t, so you will have to make sense out of the value of t above.

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