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August 31, 2014

August 31, 2014

Posted by **Ed** on Monday, January 10, 2011 at 12:16pm.

My solution:

C(5,0)x5 + C(5,1)(x4)(-1/x) + C(5,2)(x3)(-1/x)2

x5 + (5)(x4)(-1/x) + 10(x3)(-1/x)2

x5 + (-5x4/x) + 10(x3)(1/x2)

x5 + (-5x3) + 10(x)

x5 -5x3 + 10x

The first three terms are x5, -5x3, and 10x, respectably.

Is this right? Thanks a lot.

- Math -
**Reiny**, Monday, January 10, 2011 at 12:28pmI agree.

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