i am a mixed decimal number the sum of my whole number is equal to the sum of my decimal number. my tenths is half of my hundredths and my ones is twice my tenths. if all my digit are even and my hundredths is 8 what number am i. pls. answer my question tnx

Assume that the number is AB.CD

sum of my whole number is equal to the sum of my decimal number

A+B=C+D

my tenths is half of my hundredths

2C=D

my ones is twice my tenths

2B=A

my hundredths is 8
D=8

so from 2C=D, C=4

A+B=C+D=4+8=12

A+B=12 and 2B=A

2B+B=12 so B=4 and A=8

so number is

84.48

which also agrees with

all my digit are even

4.30

I have 1 hundreds 4 ones 2 tens and 1 tenths. What number am i?

have 13 hundreds, 1 tens, 7 ones, 5 tenths and 19 hundredths, what number am I?

To find the number described, we can break down the information given and follow these steps:

1. The tenths digit is half the value of the hundredths digit. Since the hundredths digit is 8, the tenths digit would be half of 8, which is 4.

2. The ones digit is twice the value of the tenths digit. Since the tenths digit is 4, the ones digit would be twice that, which is 8.

3. The sum of the whole number is equal to the sum of the decimal number. Since we have a ones digit of 8, we can assign 1 to the tens digit, and the sum would be 1 + 8 = 9.

Putting it all together, we have:

Whole number: 19
Decimal number: 0.48

Therefore, the mixed decimal number described is 19.48.