Homework Help: trigonometry

Posted by alex on Sunday, January 9, 2011 at 11:09pm.

this is exactly how the question is written and i tried to solve it but i just couldn't. Can u please show me how the work was done I dont want just the answer.

using the exact values,find the value of:

12 sin 30degrees - 6 tan of 45 degress + sec 45 degrees / 52.

please help!

trigonometry - helper, Monday, January 10, 2011 at 12:04am
12 sin 30degrees - 6 tan of 45 degress + sec 45 degrees / 52.
sin 30 = 1/2
tan 45 = 1
sec 45 = sqrt(2)

12 * 1/2 - 6 * 1 + sqrt(2)/52
12/2 - 6 + sqrt(2)/52
6 - 6 + sqrt(2)/52
0 + sqrt(2)/52 = sqrt(2)/52
trigonometry - alex, Monday, January 10, 2011 at 12:26am
thanks !
trigonometry - helper, Monday, January 10, 2011 at 12:38am
you're welcome!

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