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December 21, 2014

December 21, 2014

Posted by **alex** on Sunday, January 9, 2011 at 11:09pm.

using the exact values,find the value of:

12 sin 30degrees - 6 tan of 45 degress + sec 45 degrees / 52.

please help!

- trigonometry -
**helper**, Monday, January 10, 2011 at 12:04am12 sin 30degrees - 6 tan of 45 degress + sec 45 degrees / 52.

sin 30 = 1/2

tan 45 = 1

sec 45 = sqrt(2)

12 * 1/2 - 6 * 1 + sqrt(2)/52

12/2 - 6 + sqrt(2)/52

6 - 6 + sqrt(2)/52

0 + sqrt(2)/52 = sqrt(2)/52

- trigonometry -
**alex**, Monday, January 10, 2011 at 12:26amthanks !

- trigonometry -
**helper**, Monday, January 10, 2011 at 12:38amyou're welcome!

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