Posted by Ed on .
Using the binomial theorem, Find the first three terms in the expansion of (x(1/x))^5.
My solution:
C(5,0)x5 + C(5,1)(x4)(1/x) + C(5,2)(x3)(1/x)2
x5 + (5)(x4)(1/x) + 10(x3)(1/x)2
x5 + (5x4/x) + 10(x3)(1/x2)
x5 + (5x3) + 10(x)
x5 5x3 + 10x
The first three terms are x5, 5x3, and 10x, respectably.
Is this right? Thanks a lot.

Math 
casey,
what is the answer ?