Posted by Kevin on Sunday, January 9, 2011 at 10:13pm.
1.
mL x M = mL x M
2. How much does 1 L of the solution weigh.
1.84*1000 mL = 1840
How many grams H2SO4 are there? 18.4 moles x 98 g/mol = 1803.2 (confirm that).
%H2SO4 = (g H2SO4/g solution)*100 = ??
3. This is a stoichiometry problem. Here is a solved example problem. Just follow the steps. (The other product is Na2SO4.)
http://www.jiskha.com/science/chemistry/stoichiometry.html
4. Take 1,000 mL of the solution. That's 5.2 M = 5.2 moles H2SO4/L soln
How many g H2SO4 are in the soln? That's 5.2 x 98 g H2SO4/mol = 509.6 g
How much does the soln weigh? That's 1.38 g/mL x 1000 mL = 1380 g.
How much does the water weigh? That's 1380 g - 509.6 = ??
molality = 5.2 moles/L soln.
My answer is about 5.97 but you should confirm that.
370 mL
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