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Posted by ann on Sunday, January 9, 2011 at 9:54pm.

function f(x)=2x^2-3x f(0)= f(-1)= f(2)=

f(x) = 2x^2-3x f(0) = 2(0)^2-3(0) = 0 f(-1) = 2(-1)^2-3(-1) f(2)=?

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