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January 27, 2015

January 27, 2015

Posted by **ann** on Sunday, January 9, 2011 at 9:54pm.

f(x)=2x^2-3x

f(0)=

f(-1)=

f(2)=

- algebra -
**Marth**, Sunday, January 9, 2011 at 9:55pmf(x) = 2x^2-3x

f(0) = 2(0)^2-3(0) = 0

f(-1) = 2(-1)^2-3(-1)

f(2)=?

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