Block A (60 N) and block B (40 N) are connected by a massless cord and are AT REST. Given ìs = 0.8.
The friction on A is :
1. 40 N
2. 0 N
3. 24 N
4. 48 N
5. 20 N
6. 60 N
7. 16 N
It depends upon whether they are on an incline and whether the cord is stretched.
which answer drwls
To determine the friction on Block A, we need to consider the forces acting on the system.
First, we have the weight of each block, which is the force exerted by gravity. For Block A, the weight is given as 60 N, and for Block B, the weight is given as 40 N.
Next, we have the tension in the cord that connects the two blocks. Since the system is at rest, the tension in the cord must be equal to the combined weight of the two blocks. Therefore, the tension in the cord is (60 N + 40 N) = 100 N.
Now, let's consider the friction on Block A. The force of friction can be calculated using the formula:
friction = (coefficient of friction) * (normal force)
The normal force acting on Block A is equal to its weight since it is on a horizontal surface. Therefore, the normal force on Block A is 60 N.
Plugging in the given coefficient of friction (ìs = 0.8) and the normal force (60 N), we can calculate the frictional force on Block A:
friction = (0.8) * (60 N) = 48 N.
Therefore, the correct answer is option 4: 48 N.