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November 22, 2014

November 22, 2014

Posted by **Sebrenia** on Sunday, January 9, 2011 at 9:41pm.

- geometry -
**drwls**, Monday, January 10, 2011 at 3:31amLet X be the horizontal distance from which the 55 degree elevation angle was measured.

H/X = tan 55

H/(X + 75) = tan 40

Solve those two equations for H and X.

(X+75)/X = tan 55/ tan 40 = 1.702

1 + 75/X = 1.702

75/X = 0.702

X = 106.8 m

H = 106.8 tan 55 = 153 ft (rounded to nearest integer foot)

- geometry -
**Anonymous**, Wednesday, June 26, 2013 at 9:57amAn observer on the ground is x meters from the base of the launch pad of a rocket, which is at the same level as the observer. A few seconds after the rocket takes off vertically, the observer sees its tip at an angle of q° from the horizontal. How far above the ground is the tip of the rocket at that instant? Assume that the ground is level

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