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March 30, 2017

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Two cards are drawn without replacement from a deck of 52 cards.
Determine P(A and B) where
A : the first card is a spade
B: the second card is a face card

please help!!

  • MATH!! probability - ,

    Since a tutor hasn't answer I'll try

    A. 1st is a spade
    P = S/N
    Number of spades in deck = 13 = S
    Number of cards = 52 = N
    P = S/N = 13/52 = 1/4

    B. 2nd is a face card
    P = S/N
    Number of face cards in deck = 13 = S
    Number of cards = 52 - 1 = 51 = N
    P = S/N = 13/51

    P = P(A) * P(B)
    P = 1/4 * 13/51 = 13/204

    Not a tutor but I think it is correct
    maybe a tutor will answer

  • MATH!! probability - ,

    number of spades = 13
    number of face cards = 12
    number of face OR faces = 21

    P(A and B) = P(A) + P(b) - P(A or B)
    = 13/52 + 12/52 - 21/52 = 4/52 = 1/13

  • MATH!! probability - ,

    Number of Spades in deck=1/13

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