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January 27, 2015

January 27, 2015

Posted by **chris** on Sunday, January 9, 2011 at 8:44pm.

Determine P(A and B) where

A : the first card is a spade

B: the second card is a face card

please help!!

- MATH!! probability -
**helper**, Sunday, January 9, 2011 at 9:48pmSince a tutor hasn't answer I'll try

A. 1st is a spade

P = S/N

Number of spades in deck = 13 = S

Number of cards = 52 = N

P = S/N = 13/52 = 1/4

B. 2nd is a face card

P = S/N

Number of face cards in deck = 13 = S

Number of cards = 52 - 1 = 51 = N

P = S/N = 13/51

P = P(A) * P(B)

P = 1/4 * 13/51 = 13/204

Not a tutor but I think it is correct

maybe a tutor will answer

- MATH!! probability -
**Reiny**, Monday, January 10, 2011 at 9:58amnumber of spades = 13

number of face cards = 12

number of face OR faces = 21

P(A and B) = P(A) + P(b) - P(A or B)

= 13/52 + 12/52 - 21/52 = 4/52 = 1/13

- MATH!! probability -
**fernando torres**, Monday, June 30, 2014 at 7:12amNumber of Spades in deck=1/13

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