using the balanced reaction equation for the combustion of propane, determine the number ofmoles of oxygen that would react with.50 mol propane and the number of moles of carbon dioxide that would be produced?

C3H8 + 5O2 ==> 3CO2 +4H2O

The coefficients tell you.
1 mole C3H8 requires 5 moles O2 and produces 3 moles CO2 and 4 moles H2O for complete combustion. Just scale everything up from 1 mole C3H8 to 50 moles C3H8.

To determine the number of moles of oxygen that would react with 0.50 mol of propane (C3H8) and the number of moles of carbon dioxide (CO2) that would be produced, we need to look at the balanced equation for the combustion of propane.

The balanced equation for the combustion of propane is:
C3H8 + 5O2 -> 3CO2 + 4H2O

From the balanced equation, we can see that for every 1 mole of propane (C3H8) that reacts, we need 5 moles of oxygen (O2). Therefore, if we have 0.50 moles of propane, the number of moles of oxygen that would react can be calculated as:

Number of moles of oxygen = 0.50 mol propane * (5 mol oxygen / 1 mol propane)
Number of moles of oxygen = 0.50 mol propane * 5
Number of moles of oxygen = 2.50 mol oxygen

So, 2.50 moles of oxygen would react with 0.50 moles of propane.

Now, to determine the number of moles of carbon dioxide that would be produced, we can use the balanced equation. From the equation, we can see that for every 1 mole of propane that reacts, 3 moles of carbon dioxide are produced. Therefore, the number of moles of carbon dioxide can be calculated as:

Number of moles of carbon dioxide = 0.50 mol propane * (3 mol carbon dioxide / 1 mol propane)
Number of moles of carbon dioxide = 0.50 mol propane * 3
Number of moles of carbon dioxide = 1.50 mol carbon dioxide

So, 1.50 moles of carbon dioxide would be produced when 0.50 moles of propane react.