Wednesday
October 1, 2014

Homework Help: physics

Posted by Haley on Sunday, January 9, 2011 at 1:24pm.

A tightly stretched "high wire" is 44 m long. It sags 3.8 m when a 56 kg tightrope walker stands at its center. What is the tension in the wire?
1 NIs it possible to increase the tension in the wire so that there is no sag?


so far i know you do the inverse sin of (3.8/22) to find theta
then (56x9.8)/2 to get 274

however, now im stuck at sin(9.95)/sin(9.95)= (274)/(3.8x9.8)

i can't figure out if i did the wrong equation or just why i am stuck.

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