if 150g of Ca(OH)2 is reacted with excess H2, how much energy will be needed?
Write and balance the equation. It should look something like this.
Ca(OH)2 + H2 ==> CaH2 + H2O You balance.
Delta Hrxn = (n*delta H products)-(n*delta H reactants)
Ca(OH)2 + H2 ==> CaH2 + H2O You balance.
Delta Hrxn = (n*delta H products)-(n*delta H reactants)