thermodynamic
posted by chris on .
Energy is added to a pistoncylinder arrangement. The piston is withdrawn in such a way that the temperature remains constant. The initial pressure and volume are 200 KPa and 2m^3, respectively. If the final pressure is 100 KPa, determine the work done by the ideal gas on the piston. ( Assume T1 & T2 are constant)

If temperature is constant,
P = Po*Vo/V
and Work out = Integral of P dV
(from V1 to V2)
= (Po*Vo) * Integral of dV/V
= Po*Vo ln(V2/V1)
= Po*Vo ln(P1/P2)
= 400 ln2 kJ