a weaver spends $420 on supplies to make wall hangings and plans to sell the wall hangings for $80 each.
a. write an inequality that gives the possible numbers of (w) wall hangings the weaver needs to sell in order for the profit to be positive
b. what are the possible numbers of wall hangings the weaver needs to sell in order for the profit to be positive
a. $80 ea, w = number of wall hangings
$420 total spent
80w > 420
b. w > 5.25
she can't sell .25 of a hanging so,
she would have to sell 6 for a positive profit of $60. (6 @ 80 ex = 480,
480 - 420 = 60)
I am not a tutor.
your club is in charge of making pins that students can buy to show their school spirit for the upcoming football game.you have made 225 pins so far,you only have 2hours left to make the rest of the pins.you need to make at least 400 pins
p=number of pins/min
225+120p greater than or equal to 400
p greater than or equal to 1.46
They need to make about 2 pins per min.
To answer this question, we need to consider the costs and revenue associated with selling the wall hangings. Let's break down the problem step by step.
a. To write an inequality for the possible numbers of wall hangings needed to make a positive profit, we need to compare the revenue with the cost.
Let's assume the weaver sells "w" wall hangings. The revenue generated from selling the wall hangings would be the selling price per wall hanging multiplied by the number of wall hangings sold, which is 80w.
The cost of the supplies for making wall hangings is given as $420. Since the weaver spends this amount regardless of the number of wall hangings made, it can be considered a fixed cost.
To make a positive profit, the revenue should be greater than the cost. Therefore, the inequality would be:
Revenue > Cost
80w > 420
Now let's solve this inequality for the possible number of wall hangings.
b. To find the possible numbers of wall hangings the weaver needs to sell for the profit to be positive, we can solve the inequality:
80w > 420
To isolate "w" on one side, we can divide both sides by 80:
w > 420/80
w > 5.25
Since the number of wall hangings cannot be fractional, we round up the result to the nearest whole number, which gives us:
w > 6
Therefore, the weaver needs to sell at least 6 wall hangings in order to make a positive profit.