A mechanical toy on a circular track goes forward 3in. and then backwards 2in. How many MOVES does the toy take to complete one 15in. revoltion of the track?
It makes a net motion of one inch forward on each move, right?
I think it would be
n(3 - 2) = 15
n = 15
I tried this formula for different variations, ie, forward 3, back 1 for 6 in revolution, forward 4, back 2 for 8 in revolution and it worked.
I am not a tutor.
To determine how many moves the toy takes to complete one 15-inch revolution of the track, we need to consider the distance the toy moves in each individual move.
In each complete move, the toy goes forward 3 inches and then backward 2 inches, covering a total distance of 3 + 2 = 5 inches per move.
To complete a 15-inch revolution, we need to calculate how many moves it would take to cover 15 inches. We can do this by dividing the total distance (15 inches) by the distance covered in each move (5 inches):
Number of moves = Total distance / Distance covered in each move
Number of moves = 15 inches / 5 inches = 3 moves
Therefore, the toy takes 3 moves to complete one 15-inch revolution of the track.